You are designing a weather rocket is be launched from rest, vertically upward o

Question

You are designing a weather rocket is be launched from rest, vertically upward off the ground. The engine burn will last for 2.6 s. If the positive y direction is upward, away from the ground, then the acceleration during the engine burn (including the influence of gravity) is a_y (t) = bt^3 with b 19.61 m/s^5 and t the time from engine ignition. After the engine burns out, the acceleration is then a_y (t) = -g How long after the engine burns out does the rocket take to reach its maximum height?

Explanation / Answer

a(t) = 19.61 t3

vt = 19.61 * t4/4

t = 2.6 s

v = 19.61 * 2.64/4 = 224 m/s

v = a t

t = 224 / 9.8

t = 22.86 s

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.