Determine magnitude of the electric field at the point P shown in the figure(Fig

Question

Determine magnitude of the electric field at the point P shown in the figure(Figure 1). The two charges are separated by a distance 2a. Point P is on the perpendicular bisector of the line joining the charges, a distance z from the midpoint between them Express your answer in terms of Q, z, a, and k. E = Determine the direction of the electric field. Assume that the positive x and y axes are directed to the right and upward respectively in the negative y direction in the positive y direction in the negative x direction in the positive x direction

Explanation / Answer

As we know that

electric field due to a "+Q" charge at a point "p" = k*Q/(a2 + x2)

Direction of electric field due to a "+Q" charge at a point "p" = line joining the charge Q and p away from the charge +Q

electric field due to a "-Q" charge at a point "p" = k*Q/(a2 + x2)

Direction of electric field due to a "-Q" charge at a point "p" = line joining the charge Q and p towards the charge -Q

So

So

the resultant electric field at point "p" is = 2*k*Q/(a2 + x2)

Direction of the resultant electric field at point "p" is only in "-Y" Direction because electric field in x direction cancel out

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