Was the sum of the measured voltages across the individual resistors in the seri
ID: 1532744 • Letter: W
Question
Was the sum of the measured voltages across the individual resistors in the series circuit equal to the measured voltage across the combination? Is this result to be expected? Explain briefly. Was the sum of the measured currents through the individual resistors in the parallel circuit equal to the measured total current? Is this result to be expected? Explain briefly. Were the voltages across the individual resistors in the parallel circuit the same? Explain briefly. Do your experimental results support the series and parallel formulas for combinations of resistances? Discuss. At the junction of two resistors an electric current will split and part of the charge will flow through one resistance and the remainder of the charge through the other resistance. Which resistance has the larger current through it? Why? State a situation analogous to the electrical situation of Question 5, involving water flowing through pipes.Explanation / Answer
1)The sum of voltages across individual resistors in the series circuit should equal to the supplied voltage.
Current is same for the devices connected in series, so if R and I are known, you can caluclate the drop using V = IR. The drop across all should sum to the batter/supply voltage.
2)The current though individual resistors in parallel is different if the resistors have different values. for all the resistors in the parallel combination, the sum of the current should be equal to the current supplied by the battery.
I = V/Req
3)Yes, its a fact that the voltage acoss the resistors connected in parallel is same.
4)This question is based on your observation.
For an ideal circuit, it should support.
5)I = V/R
The resistor, which has more potential drop will have more current though it.
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