Exercise 3.9 A physics book slides off a horizontal table top with a speed of 1.

Question

Exercise 3.9 A physics book slides off a horizontal table top with a speed of 1.20 m/s. It strikes the floor after a time of 0.380 s. Ignore air resistance. Part A Find the height of the table top above the floor. 7.3 Submit My Answers Give Up Incorrect; Try Again; 5 attempts remaining Part B Find the horizontal distance from the edge of the table to the point where the book strikes the foor. SubmN My Answers Give Up Part C Find the horizontal component of the book's velocity just before the book reaches the foor

Explanation / Answer

A.Find the height of the tabletop above the floor.
h = 4.9*0.38^2 = 0.707m

B.Find the horizontal distance from the edge of the table to the point where the book strikes the floor.
d = Vo*t = 1.2*0.358= 0.456 m

C.Find the horizontal component of the book's velocity, just before the book reaches the floor.
Vx = Vi = 1.20 m/sec

D.Find the vertical component of the book's velocity just before the book reaches the floor.
Vy = 2gh = 19.6+0.707 = 3.72 m/sec

E.Find the magnitude of book's velocity, just before the book reaches the floor.
V = Vx^2+Vy^2 = 3.72^2+1.20^2 = 3,91m/sec

F.Find the direction of book's velocity, just before the book reaches the floor.
= arctan(3.91/1.2) = 7294°

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