Daredevil Dan gets in his rocket car and accelerates from rest at 2g (2 times th
ID: 1533166 • Letter: D
Question
Daredevil Dan gets in his rocket car and accelerates from rest at 2g (2 times that of gravity). Unfortunately for Dan, he picks a poor spot for his stunt. After accelerating for 200 feet he drives right off a 10 foot high ledge. If he keeps accelerating the whole time, how far does he land after going off the ledge? (Assume the rocket remains level the whole time until it crashes) Daredevil Dan gets in his rocket car and accelerates from rest at 2g (2 times that of gravity). Unfortunately for Dan, he picks a poor spot for his stunt. After accelerating for 200 feet he drives right off a 10 foot high ledge. If he keeps accelerating the whole time, how far does he land after going off the ledge? (Assume the rocket remains level the whole time until it crashes)Explanation / Answer
acceleration ax = 2g = 2*32 ft/s = 64 ft/s^2
speed at the end of legde vx = sqrt(2*a*x) = sqrt(2*64*200) = 160 ft/s
along vertical
initial velocity v0y = 0
acceelration ay = 32 ft/s^2
displacement y = -10 ft
y = v0y*t + (1/2)*ay*t^2
-10 = 0 - (1/2)*32*t^2
t = 0.791 s
along horizontal
x = vx*t + (1/2)*ax*t^2
x = (160*0.791) + (1/2)*64*0.791^2
x = 146.5 ft <<<<<---------answer
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