mibiscms/modlibisNiew.php?id-3390899 Gradebook Question 10 of 13 Bob has just fr

Question

mibiscms/modlibisNiew.php?id-3390899 Gradebook Question 10 of 13 Bob has just frished cimbing a sheer cimabove a beach and wants to Sgure out how high hedimbed. the bajectoryN and 0.910 seconds the ball is once again level with Bob Bob can see wel enough to time when the bal hits the then that the ball landed mfrom the base of the cit.How high upis Bobirthe ball started from exactly 2m above the edge of the 32.1 m/s r. 0.910 s 2 m 124 m O Previous checks Anwer ONed Due Dat Grade Ca You can ch You can vi You can ke you get it There is no on the num O eTextbook O Help With o Web Help O Technical

Explanation / Answer

t = 2 v0 sin theta / g

0.910 = (2 * 32.1 * sin theta) / 9.8

theta = 7.98 deg

tf = R / v0 cos theta = 124 / 32.1 * cos 7.98

= 3.90 s

h = -(vy sin theta) t + 1/2 g t2

= -(32.1 sin 7.98) 3.90 + 1/2 * 9.8 * 3.902 = 57.15 m

H = h - 2 = 55.15 m

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