Review Conceptual Example 3 and the drawing as an aid in solving this problem. A

Question

Review Conceptual Example 3 and the drawing as an aid in solving this problem. A conducting rod slides down between two frictionless vertical copper tracks at a constant speed of 3.2 m/s perpendicular to a 0.43-T magnetic field. The resistance of the rod and tracks is negligible. The rod maintains electrical contact with the tracks at all times and has a length of 1.9 m. A 1.0 -Ohm resistor is attached between the tops of the tracks, What is the mass of the rod? Find the change in the gravitational potential energy that occurs in a time of 0.28 s. Find the electrical energy dissipated In the resistor in 0.28 s.

Explanation / Answer

b) change in gravitational potential energy,

delta_U = U2 - U1

= m*g*h2 - m*g*h1

= m*g*(h2 - h1)

= m*g*(-h)

= -m*g*h

= -m*g*(v*t)

= -0.22*9.8*(3.2*0.28)

= -1.93 J

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