Please post an explanation of the solution as well as the solution itself Two cy

Question

Please post an explanation of the solution as well as the solution itself

Two cylindrical resistors are made from the same material and are equal, in length. The first resistor has diameter d, and the second resistor has diameter 2d. If the same current flows through both, compare the voltage across the two resistors: V_1 > V_2 V_1 = V_2 V_1 > V_2 Briefly explain your reasoning Two cylindrical resistors are made from the same material and are equal in diameter. The first resistor has length L, and the second resistor has length 2L. If the same current flows through both, compare the voltage across the two resistor: V_1 > V_2 V_1 = V_2 V_1 > V_2

Explanation / Answer

1)
correc option is V1 > V2

2) I1 = I2

R = pL/A

R= 4pL/pi*d^2

R1= 4pL/pi*d^2

R2= 4pL/pi*4d^2

R1/R2 = 4

from ohms law V = IR

V1/V2 = R1/R2 = 4

V1>V2

if diameter is increased resistance is decreased and voltage also decreased across second resistor

3)
correc option is V1 > V2

4) I1 = I2

R = pL/A

R1= 4pL/pi*d^2

R2= 4p*2L/pi*d^2

R1/R2 = 1/2

from ohms law V = IR

V1/V2 = R1/R2 = 1/2

V1 < V2

if distance is inreased resistance is increased and voltage also increased across second resistor

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