Problem 20.28 A straight 2.20 m wire carries a typical household current of 1.50

Question

Problem 20.28

A straight 2.20 m wire carries a typical household current of 1.50 A (in one direction) at a location where the earth's magnetic field is 0.550 gaussfrom south to north.

Part A

Find the direction of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from west to east.

Please Choose

The force is directed upward.

The force is directed downward.

There is no force exerting on the wire.

The force is directed from east to west.

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Part B

Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from west to east.

N

Part C

Find the direction of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running vertically upward.

Please ChooseThe force is directed from east to west. The force is directed from west to east. The force is directed from north to south. The force is directed from south to north.

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Part D

Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running vertically upward.

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Part E

Find the direction of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from north to south.

Please ChooseThe force is directed upward. The force is directed downward. There is no force exerting on the wire. The force is directed from north to south.

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Part F

Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from north to south.

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Part G

Is the magnetic force ever large enough to cause significant effects under normal household conditions?

yes or no

Problem 20.28

A straight 2.20 m wire carries a typical household current of 1.50 A (in one direction) at a location where the earth's magnetic field is 0.550 gaussfrom south to north.

Part A

Find the direction of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from west to east.

Please Choose

The force is directed upward.

The force is directed downward.

There is no force exerting on the wire.

The force is directed from east to west.

SubmitMy AnswersGive Up

Part B

Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from west to east.

F1=

N

Part C

Find the direction of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running vertically upward.

Please ChooseThe force is directed from east to west. The force is directed from west to east. The force is directed from north to south. The force is directed from south to north.

SubmitMy AnswersGive Up

Part D

Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running vertically upward.

F2= N

SubmitMy AnswersGive Up

Part E

Find the direction of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from north to south.

Please ChooseThe force is directed upward. The force is directed downward. There is no force exerting on the wire. The force is directed from north to south.

SubmitMy AnswersGive Up

Part F

Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from north to south.

F3= N

SubmitMy AnswersGive Up

Part G

Is the magnetic force ever large enough to cause significant effects under normal household conditions?

yes or no

Explanation / Answer

A. Out of the page (upward).

B. F = I*B*L*sin
=(1.5A)(.550x10^-4T)(2.20 m)sin90

=1.815x10^-4N

C. West (to the left)

D (1.5A)(.550x10^-4T)(2.20 m)sin90

E.No.

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