A student constructed the circuit shown in the figure. The currents through resi

Question

A student constructed the circuit shown in the figure. The currents through resistors R_1, R_2 and R_4 are 2.00A, 5.00A, and 3.00A respectively, Write the junction rule at points a, b, c and d. Write the loop rule applied to loop cdac. Write the loop rule applied to loop cbac. Write the loop rule applied to loop bdcb. Calculate the current in the R_3, the unknown emfs and the resistance R_1. Please use symbolic algebra to solve this problem until last step. Make sure to follow the loop direction as indicated as well as the rules we teach von in laboratory Manual. Use R_2 = 6.00 Ohm, R_3 = 3.00 Ohm, and R4 = 4.00 Ohm.

Explanation / Answer

here,

R2 = 6 ohm , R3 = 3 ohm

R4 = 4 ohm

I1 = 2 A , I2 = 5 A

I4 = 3 A

a)

at junction a

using KCL

I3 = I4 + I2 ....(1)

at juction b

I5 = I1 + I2 ....(2)

at juction c

using KCL

I3 = I6 + I5 ...(3)

at juntcion d

using KCL

I4 = I1 + I6 ....(4)

b)

using loop rule in cdac

I4 * R4 + I3 * R3 = E1 ...(5)

c)

using loop rule in loop cbac

R2 * I2 + R3 * I3 = E2 ....(6)

d)

using loop rule in loop bdcb

I1 * R1 = E2 - E1 ....(7)

e)

from (1) , (2) , (3) , (4) , (5) , (6 )and 7

I3 = 8 A

E1 = 36 V

E2 = 54 V

R1 = 9 ohm

I5 = 7 A

I6 = 1 A

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