In the picture below, the two wires carry current i_1 and ¡_2, respectively, wit
ID: 1534225 • Letter: I
Question
In the picture below, the two wires carry current i_1 and ¡_2, respectively, with positive current to the right. The charge q is positive and has velocity v to the right. If ¡_2 = 0 and i_1 is greater than zero, then the force on q is north. If ¡_2 = - ¡_1 then the force on q equals zero. If v = 0, then the force on q is zero. If ¡_2 = 0 and i_1 is greater than zero, then the magnetic field near charge q points out of the page. If i_1 = 0 and ¡_2 is greater than zero, then the force on q points out of the page. If ¡_1 is greater than ¡_2, then the force on q is north. If ¡_1 = ¡_2, then the wires are attracted to each other.Explanation / Answer
a) True F = q*( VxB)
b) False
net force will doubles
c) True
d) False
magnetic field is into the page.
e) False
force is in south
f) True
g) True
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