A block of mass m_t = 6.00 kg is put on top of a block of mass m_b = 6.00 kg. To

Question

A block of mass m_t = 6.00 kg is put on top of a block of mass m_b = 6.00 kg. To cause the top block to slip on the bottom one while the bottom one is held fixed, a horizontal force of at least 15.0 N must be applied to the top block. The assembly of blocks is now placed on a horizontal, frictionless table (see the figure). Find the magnitudes of (a) the maximum horizontal force vector F that can be applied to the lower block so that the blocks will move together and (b) the resulting acceleration of the blocks.

Explanation / Answer

(b)

a = F1 / mt

a = 15 / 6 = 2.5 m/s^2

(a)

maximaum force is,

F = (mt + mb)*a

F = 12*2.5 = 30 N

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