Help with my homework please! Show all work. Thanks! X and Y are two initially u

Question

Help with my homework please!

Show all work. Thanks!

X and Y are two initially uncharged metal spheres on insulating stands, and they are in contact with each other. A positively charged rod R is brought close to X as shown in part (a) of the figure. Sphere Y is now moved away from X, as shown in part (b). What are the final charge states of X and Y? Both X and Y are neutral. X is positive and Y is neutral. X is negative and Y is positive. Both X and Y are negative. X is neutral and Y is positive. Two tiny beads are 25 cm apart with no other charges or fields present. Bead A carries 10 mu C of charge and bead B carries 1 mu C. Which one of the following statements is true about the magnitudes of the electric forces on these beads? The force on A is exactly equal to the force on B. The force on A is 10 times the force on B. The force on A is 100 times the force on B. The force on B is 100 times the force on A. The force on B is 10 times the force on A. Two point charges, Q_1 and Q_2, are separated by a distance R. If the magnitudes of both charges are doubled and their separation is also doubled, what happens to the electrical force that each charge exerts on the other one? It increases by a factor of 2. It increases by a factor of squareroot 2. It increases by a factor of 4. It remains the same. It is reduced by a factor of squareroot 2.

Explanation / Answer

1)

when x and Y are in contact ,the near end of x to the rod is negatively charged and far end is positively charged

after seperation X becomes Negatively chaarged and Y becomes positively charged

so the correct option is C)

2) By the Newto's third law of motion

Force on A by B = - Force on B by A

So the correct option is A)

3) F1 = k*Q1*Q2/d^2

F2 = k*2*Q1*2Q2/(2*d)^2 = k*Q1*Q2/d^2 = F1

Force remains same

So the correct choice is D)

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