A simple pendulum, 2.0 length is released with a push when the support string is

Question

A simple pendulum, 2.0 length is released with a push when the support string is at an angle of 25 degree from the vertical the initial speed of the suspended mass is 1.2 m/s when at the release point, what is speed at the bottom of the swing? (Use the mechanical energy conservation law to solve the problem) A speed boat requires 80 kW to move at a constant speed of 15 m/s What is the resistive force of the water at this speed? A projectile is launched with an initial speed of 30. 0 m/s at an angle of 30. 0 degree above the horizontal. The projectile lands on a hillside 2.00 s later. Neglect air friction. What is the highest projectile's velocity at the highest point of its trajectory? What is the straight-line distance from where the projectile was launched its where it (Note that the hill may slope up or down from the launch was launched to point.) If the system is set in motion with m_1 = 9.00 kg and m_2 = 5.00 kg. The coefficient of kinetic friction is 0.30. If the system is set in motion with m_2 moving downward, what will be the magnitude of the string tension? A sports car dealer claims that his product will accelerate at a constant rate from rest to a speed of 8.00 s. Find the sports car acceleration. the distance the sports car will travel the acceleration period. A ball is rolled horizontally off a table with an initial speed of 0.92 m/s. me height of the table is 44 cm. With what speed will the ball hit the floor? A 20 kg traffic light hangs midway on a cable between two poles 40 m apart. If the sag in the cable what is the tension in each side of the cable?

Explanation / Answer

6] vertical velocity v = sqrt(2gh) = sqrt(2*9.8*0.44) = 2.936 m/s

speed of hitting = sqrt(2.936^2+ 0.92^2) = 3.0767 m/s answer

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