detailed solution please In the impulse-momentum diagram to the right, the 2 or
ID: 1535530 • Letter: D
Question
detailed solution please
In the impulse-momentum diagram to the right, the 2 or tennis ball initially travels to the left at 61mph when the tennis racket strikes it, mV exerting an impulse L1 rightarrow 2 = 0.4 i 0.4 j lb. s on the ball. The ball is 1 ft above the ground when the State 1 tennis racket impacts it. Determine maximum 1 2 height the tennis ball achieves above the horizontal tennis court and its velocity at this instant. Neglect air drag (probably not a good assumption for a tennis ball)Explanation / Answer
mass m = 2*0.0283 kg
initial momentum Pi = -m*v1 i
v1 = 61 mph = 61*0.45 = 27.45 m/s
final momentum Pf = m*v2
Impulse L = 0.4i + 0.4 i
from impulse momentum theorem
impulse = change in momentum
L = Pf - Pi
0.4i + 0.4j = 0.028*(v2 + 2.45i)
v2 = 11.85 i + 14.3 j
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along vertical
initial velocity v0y = 14.3 m/s
y0 = 1 ft = 0.3048 m
acceleration ay = -g = -9.8 m/s^2
at maximum height vy = 0
vy^2 - v0y^2 = 2*ay*dy
0 - 14.3^2 = -2*9.8*(y-0.3048)
ymax = 10.7 m <<<<---answer
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velocity at maxim height = 11.85 i
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