The figure below shows the light intensity on a screen behind a double slit expe

Question

The figure below shows the light intensity on a screen behind a double slit experiment. The "tallest" peak in the figure corresponds to the m= 0 maximum. The next peak, to the right or left, will be an m = 1 maximum. The distance shown in the figure below and labeled as y is 2.2 cm. The slit spacing is 0.20 mm and the wavelength of the light is 690 nm. What is the value of m for the right-most peak (maximum)? 2 What is the distance between the central maximum and the right-most peak that corresponds to the m that you got for part (a)? Please give this distance in meters ____ m What is the distance from the slits to the screen? Please give this distance in meters. _____ m

Explanation / Answer

a) m = 2

b) y = (2.2*10^-2)/2 = 1.1*10^-2 = 0.011 m

c) distance from central maximum to second bright fringe

y = m*lamda*L/d

0.011 = 2*690*10^-9*L/(0.2*10^-3)

L = 1.59 m

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