US Halliday, Fundamentals of Physics, 10e Help l System Announcements Cunread) m

Question

US Halliday, Fundamentals of Physics, 10e Help l System Announcements Cunread) ment NEXT PRINTER VERSION Chapter 09, Problem o31 Flying Circus of Physics Jumping up before the elevator the cable snaps and the safety system from a height of 30.0 During the collision at the bottom of the elevator shaft, a kg passenger is stopped 5.00 ms. (Assume that neither the passenger nor the are the (a) and (b) average force on the passenger during the collision? If the passenger were to jump with a speed of 8.00 m/s relative to the cab floor just before the cab hits the bottom of the shaft, what are the magnitudes of the (c) impulse and (d) average force (assuming the same stopping time)? (a) Number Units (b) Number Units (c) Number (d) Number Click if you would like to show work for this question: Qpen Show Work LINK TO SAMPLE PROBLEM VIDEO MINI-LECTURE By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Question Attempts: o of 3 used SAVE FOR LATER suBMIT ANSWER Policy l 2.20020-2012 lohn Sons, unca All Rights Reserved. A Division of lohn Wuley & Sons, Inc. 4.22.1.2

Explanation / Answer

We know H=30 m

So velocity at bottom=sqrt(2*g*H)=24.25 m/s

Now impulse=change in momentum=m*v=1915.65 kgm/s

Average force=impulse/time=383129.64 N

If final velocity is 8 m/s upwards

Impulse=change in momentum=79*(24.25+8)=2547.75 kg.m/s

Average force=509550 N

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