When two charges (q_1 and q_2) are held a distance d apart from each other, each

Question

When two charges (q_1 and q_2) are held a distance d apart from each other, each exerts a force of magnitude F on the other. (a) If one of the charge's magnitude is quintupled and the distance between the charges is increased by a factor of 7, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)? (b) If both of the charge's magnitudes are quintupled and the distance between the charges is increased by a factor of 7, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)?

Explanation / Answer

two charges (q1 and q2) are held a distance d apart from each other

a) F ~ q and ~ 1/r^2; so F' = F (4)*(1/49) = 4F/49 ANS

b) F' = F (4*4)/49 = 16F/49 ANS.

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