Use the steps outlined above to find the magnitude of the acceleration a of a ch

Question

Use the steps outlined above to find the magnitude of the acceleration a of a chair and the magnitude of the normal force FN acting on the chair: Yusef pushes a chair of mass m = 50.0 kg across a carpeted floor with a force F p (the subscript 'p' here is lowercase and throughout the question) of magnitude Fp = 156 N directed at = 35.0 degrees below the horizontal (Figure 1) . The magnitude of the kinetic frictional force between the carpet and the chair is Fk = 98.5 N .

Use the component form of Newton's second law to write an expression for the x component of the net force, Fx. Express your answer in terms of some or all of the variables: FG, FN, Fp, , and  Fk .

Explanation / Answer

m = 50.0 kg

Fp = 156 N

= 35.0

Fk = 98.5 N

the net force on the chair is

F = Fp + m g sin35 - Fk

we have F = m a

F = 50 a

50 a = 156 + 50 X 9.8 X sin35 - 98.5

a = 6.77 m/sec2

the normal force is

N = m g cos35

N = 50 X 9.8 X c0s35

N = 401.384 N

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