php?id-3390900 7 10:00 PM 63/100 Print Calculator MPeriodic Table 15 of 16 Sapli

Question

php?id-3390900 7 10:00 PM 63/100 Print Calculator MPeriodic Table 15 of 16 Sapling Learning system, a crewman on 50.3 kg Donlatring to lower a 6.30*g holding rope, lower the cate constant speed of 1.50 ms tely, when the crate reaches apoint the steps patch and The immediately accelerates toward the ground, 6.30 kg 23.0 m edge of the cliff. 12.8 m assume the ice is perfectly slid (that is, no friction between the crewman and the Loe once he sips and falls down), at what speed wil the crate he the ground? Assume also thattherapeislong figure not to scale m/s At what speed will the crewman hit the bottom ofthe ravine? (Assume no air friction m/s O Previous check Answer 0Net

Explanation / Answer

here,

mass of crate , m1 = 6.3 kg

mass of crewman , m2 = 50.3 kg

initial speed , u = 1.5 m/s

the accelration of the system , a = m1 * g/(m1 + m2)

a = 6.3 *9.8 /(6.3 + 50.3)

a = 1.09 m/s^2

for crate ,

h1 = 12.8 m

the final speed be v1

v1^2 - u^2 = 2 * a * h

v1^2 - 1.5^2 = 2 * 1.09 * 12.8

v1 = 5.49 m/s

for crewman

time taken to hit the ravine be t and final speed be v2

h = 0 + 0.5 * a * t^2

12.8 = 0.5 * 1.09 * t^2

t = 4.85 s

the final vertical speed , vy = 0 + a * t

vy = 5.28 m/s

vx = 5.49 m/s

then v2 = sqrt(vx^2 + vy^2)

v2 = 7.62 m/s

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.