Let h be the height of release relative to ground level. Choose ground level as

Q: Let h be the height of release relative to ground level. Choose ground level as

Using conservation of mechanical energy initial mechnical energy = final mechanical energy (1/2)*m*vi^2 + m*g*yi = (1/2)*m*vf^2 + m*g*yf 0 + m*g*h = (1/2)*m*vf^2 + 0 (since vi = 0 , yf = 0 ) g*h = vf^2/2 ==> vf^2 = 2*g*h ==> vf = sqrt(2*g*h)

ID: 1536378 • Letter: L

Question

Let h be the height of release relative to ground level. Choose ground level as the zero of gravitational potential energy. Let vi be the initial speed of the ball, and let vf be the speed of the ball just before it hits the ground.

According to conservation of mechanical energy, the mechanical energy of the ball at the point of release (yi = h) must equal the mechanical energy at a point just above the ground, where yf = 0.

1/2 mvi^2 + mgyi = 1/2 mvf2 + mgyf

1/2 mvi2 + mgh = 1/2 mvf2 + 0

Solve this for the ball's final speed vf. (Use any variable or symbol stated above along with the following as necessary: g.)

Explanation / Answer

Using conservation of mechanical energy

initial mechnical energy = final mechanical energy

(1/2)*m*vi^2 + m*g*yi = (1/2)*m*vf^2 + m*g*yf

0 + m*g*h = (1/2)*m*vf^2 + 0 (since vi = 0 , yf = 0 )

g*h = vf^2/2

==> vf^2 = 2*g*h

==> vf = sqrt(2*g*h) <<<<<<<<<-----------Answer

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Let h be the height of release relative to ground level. Choose ground level as

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Let h be the height of release relative to ground level. Choose ground level as

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