10.01 9.77 9.938 10.046 9.964 9.967 9.765 9.79 9.983 10.049 9.97 9.837 9.98 9.91
ID: 1536474 • Letter: 1
Question
10.01 9.77 9.938 10.046 9.964 9.967 9.765 9.79 9.983 10.049 9.97 9.837 9.98 9.91 9.879 9.873 10.02 9.98 9.95 9.86 9.889 10.25 9.887 9.89 9.95 9.83 10.051 9.977 9.886 10.25 10.104 9.87 9.921 9.973 9.911 9.941 9.7883 9.86 10.09 9.973 9.86 9.911 9.8 9.92 10.056 9.98 9.95 9.8575 10.02 9.82 9.57 9.678 9.946 9.714 9.787 9.695 9.58 9.613 9.669 9.6 9.737 9.71 9.72 9.669 9.743 9.84 9.71 9.65 9.65 9.589 9.88 9.747 9.8 9.69 9.7 9.801 9.637 9.706 10.02 9.884 9.68 9.851 9.853 9.781 9.841 9.6183 9.66 9.79 9.633 9.59 9.871 9.68 9.63 9.846 9.86 9.83 9.5475 9.792.
and here is the numbers
On the class website on the homework page you will find a file called "Ml G_data_sp17." These are the collected results for a class for measurements for the acceleration of gravity g. Calculate the average, the standard deviation, and the standard error on the mean for g? State your final answer for g_avg plusminus delta g in standard format. When the prof. completed the experiment, she measured 9.79 plusminus 0.02 m/s^2. Determine if this measurement agrees or disagrees with g_avg. Explain your reasoning.Explanation / Answer
Given dataset
10.01 9.77 9.938 10.046 9.964 9.967 9.765 9.79 9.983 10.049 9.97 9.837 9.98 9.91 9.879 9.873 10.02 9.98 9.95 9.86 9.889 10.25 9.887 9.89 9.95 9.83 10.051 9.977 9.886 10.25 10.104 9.87 9.921 9.973 9.911 9.941 9.7883 9.86 10.09 9.973 9.86 9.911 9.8 9.92 10.056 9.98 9.95 9.8575 10.02 9.82 9.57 9.678 9.946 9.714 9.787 9.695 9.58 9.613 9.669 9.6 9.737 9.71 9.72 9.669 9.743 9.84 9.71 9.65 9.65 9.589 9.88 9.747 9.8 9.69 9.7 9.801 9.637 9.706 10.02 9.884 9.68 9.851 9.853 9.781 9.841 9.6183 9.66 9.79 9.633 9.59 9.871 9.68 9.63 9.846 9.86 9.83 9.5475 9.792
2. a.
Sample Size = 98 Entries
Average = sigma (xi) / sigma (i) = 9.83771
Standard Deviation = sqroot(sigma[(xi - mean)^2]/[sigma(i)]) = 0.14895
Standard Error = SD/sqroot(n) = 0.14895/sqroot(98) = 0.01504
g = 9.83771 +- 0.01504 m/s/s
b.
g measured = 9.79+-0.02 m/s/s
The maximum g in this case would be 9.81 m/s/s
the minimum g as from the data values' statistical interpretation should be 9.822 ( greater than the maximum theoretical statistical value from the teacher)
Hence there is an error in the reading as reported by the teacher
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