Calculate the terminal voltage for a battery with an internal resistance of 0.90

Question

Calculate the terminal voltage for a battery with an internal resistance of 0.900 ohm and an emf of 7.50 V when the battery is connected in series with a 89.0- ohm resistor. Express your answer to three significant figures and include the appropriate units. Calculate the terminal voltage for a battery with an internal resistance of 0.900 ohm and an emf of 7.50 V when the battery is connected in series with an 890-ohm resistor. Express your answer to three significant figures and include the appropriate units.

Explanation / Answer

Terminal voltage=(exR)/(r+R)

=(7.5x89)/(0.9+89)

=7.42v

B. Terminal voltage=(7.5x890)/(890+0.9)

=7.49v

=

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