Two identical light bulbs are connected to identical batteries in two different

Question

Two identical light bulbs are connected to identical batteries in two different ways. In method A the bulbs are connected in parallel, and the parallel combination is connected between the one battery's terminals. In method B the bulbs are connected in series, and the series combination is connected between the other battery's terminals. What is the ratio of the power supplied by the battery in method A to the power supplied in method B?
Answer is 4. Lost on how to figure this out, please show work. Thanks!

Explanation / Answer

let resistance of each bulb be R ohms and voltage of the supply is V volts.

method A:

when connected in parallel, votlage across each bulb is V .

hence power supplied=(V^2/R)+(V^2/R)=2*V^2/R

method 2:

when connected in series, net resistance=R+R=2*R

power supplied=V^2/(2*R)

so ratio=(2*V^2/R)/(V^2/(2*R))=4

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.