Assume that E = 63.5 V . The battery has negligible internal resistance. Part A

Question

Assume that E = 63.5 V . The battery has negligible internal resistance.

Part A

Compute the equivalent resistance of the network in (Figure 1) .

Express your answer in ohms to three significant figures.

SubmitMy AnswersGive Up

Part B

Find the current in the 3.00 resistor.

Express your answer in amperes to three significant figures.

SubmitMy AnswersGive Up

Part C

Find the current in the 6.00 resistor.

Express your answer in amperes to three significant figures.

SubmitMy AnswersGive Up

Part D

Find the current in the 12.0 resistor.

Express your answer in amperes to three significant figures.

SubmitMy AnswersGive Up

Part E

Find the current in the 4.00 resistor.

Express your answer in amperes to three significant figures.

SubmitMy AnswersGive Up

Provide FeedbackContinue

Figure 1 of 1

Assume that E = 63.5 V . The battery has negligible internal resistance.

Part A

Compute the equivalent resistance of the network in (Figure 1) .

Express your answer in ohms to three significant figures.

Req=     

SubmitMy AnswersGive Up

Part B

Find the current in the 3.00 resistor.

Express your answer in amperes to three significant figures.

I1=   A  

SubmitMy AnswersGive Up

Part C

Find the current in the 6.00 resistor.

Express your answer in amperes to three significant figures.

I2=   A  

SubmitMy AnswersGive Up

Part D

Find the current in the 12.0 resistor.

Express your answer in amperes to three significant figures.

I3=   A  

SubmitMy AnswersGive Up

Part E

Find the current in the 4.00 resistor.

Express your answer in amperes to three significant figures.

I4=   A  

SubmitMy AnswersGive Up

Provide FeedbackContinue

Figure 1 of 1

3.00 12.0 (2 6.00 4.00 (2

Explanation / Answer

3 ohm and 6 ohm resistances are parallel

1 / R1 = 1 / 3 + 1 / 6

R1 = 2 ohm

12 ohm and 4 ohm resistors are in parallel

1 / R2 = 1 / 12 + 1 / 4

R2 = 3

R1 and R2 are in series so,

Rnet = R1 + R2

Rnet = 2 + 3

Rnet = 5 ohm

by ohm's law

V = IR

63.5 = I * 5

I = 12.7 A

current through 3 ohm resistor = 6 * 12.7 / (3 + 6)

current through 3 ohm resistor = 8.467 A

current through 6 ohm resistor = 3 * 12.7 / (3 + 6)

current through 6 ohm resistor = 4.23 A

current through 12 ohm resistor = 4 * 12.7 / (12 + 4)

current through 12 ohm resistor = 3.175 A

current through 4 ohm resistor = 12 * 12.7 / (12 + 4)

current through 4 ohm resistor = 9.525 A

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.