Vector A^rightarrow = 6.0 m and points 30 degree south of east. Vector B^rightar

Question

Vector A^rightarrow = 6.0 m and points 30 degree south of east. Vector B^rightarrow = 4.0 m and points 30 degree west of south. The resultant vector A^rightarrow + B^rightarrow is given by 9.8 m at an angle 26 degree south of east. 3.3 m at an angle 26 degree south of east. 7.2 m at an angle 64 degree south of east. 3.3 m at an angle 64 degree south of east. 9.8 m at an angle 64 degree south of east. If the acceleration vector of an object is directed anti-parallel to the velocity vector, the object is turning. object is not moving. the object is speeding up. the object is slowing down. This situation would not be physically possible.

Explanation / Answer

A = 6 cos 30 i- 6 sin 30 j = 5.196 i - 3 j

B= - 4 sin 30 i - 4 cos 30 j= -2 i - 3.464 j

A+ B= ( 3.196 ) i - ( 6.464 ) j

magnitude of A+ B = sqroot ( 3.196 ^2 + 6.464^2) = sqroot ( 52) = 7.21 m apprx

correect option is C.

b) the object is slowing down

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