A square loop of wire with a small resistance is moved with constant speed from

Question

A square loop of wire with a small resistance is moved with constant speed from a field free region into a region of uniform B field (B is constant in time) and then back into a field free region to the left. The self-inductance of the loop is negligible. When leaving the field, the coil experiences a magnetic force to the right. When entering the field the coil experiences a magnetic force to the right. Upon entering the field, a clockwise current flow in the loop. Upon leaving the field, a counterclockwise current flow in the loop.

Explanation / Answer

1) False, From the equation force acting on currrent carrying conductor F=IL*B, and work do pull the loop in the field possible direction of force is left.

2)  False this is because direction of current anticlockwise which opposes the increase of magnetic flux. This is possible , a part loop at left hand side is in the field produces force to the left.

3) True,entering the field, clockwise current flow in the loop.

4) True, leaving the field , counterclockwise current flow in the loop.

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