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Question

C a www.webassign ret/webwstudent/Assignment-Responses/mast?depa15400846 i i Apps For quick access place your bookmaris here on the bookmarks bar. import bookmarks now. A series circuit consists of three identical lamps connected as shown in the figure below. The switch s, originally open, is closed. to a battery what then happens to the brightness of lamp B? i) what happens to the brightness of lamp C (ii) What happens to the current in the battery? (iv) What happens to the potential difference across lamp A? (v) What happens to the potential difference vi) what happens to the total power delivered to the lamps by the battery?

Explanation / Answer

when S is closed, lamp C is shorted and the net resistance in the circuit goes down

then current=voltage/resistance goes up

as power consumed =current^2*resistance of each bulb

as current goes up,power consumed also go up

part a:

brightness of lamp B goes up (as brightness is directly proportional to power consumed)

part b:

lamp C is shorted and hence gets switched off.

part c:

current in the battery increases.

part d:

potential difference across lamp A increases.

(as earlier E was divided by 3 for voltage across each lamp and now it is divided by 2 for voltage across each lampP)

part e:

potential difference across lamp C becomes 0

part f:

total power delivered =E*current through battery

as current goes up, total power delivered goes up.

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