A student stands at the edge of a cliff and throws a stone horizontally over the
ID: 1537506 • Letter: A
Question
A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of 17.0 m/s. The cliff is h = 56.0 m above a flat, horizontal beach as shown in the figure.
a)Write the equations for the x- and y-components of the velocity of the stone with time. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not state units in your answer.)
vx=
vy=
b) Write the equations for the position of the stone with time, using the coordinates in the figure. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not state units in your answer.)
x=
y=
c)How long after being released does the stone strike the beach below the cliff?
d)With what speed and angle of impact does the stone land?
vf = m/s = ° below the horizontalExplanation / Answer
a )
the x- and y-components of the velocity is
vx= 17 m/sec
vy= 0 m/sec
b )
Vx = vx = 17 m/sec
Vy = vy + g t
= 0 + 9.8 t
Vy = 9.8 t
c )
at beach y = 0
56 = 1/2 X 9.8 X t2
t2 = 11.42
t = 3.37 sec
d )
vx = 17 m/sec
vy = 9.8 X 3.37
vy = 33.026 m/sec
angle = tan-1 ( 33.026 / 17 )
= 62.76o below the horizontal
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