plinglearning.com/ibiscms/mod/ibis view.php?id 3300701 HYS 202 Winter17-TOVAR I

Question

plinglearning.com/ibiscms/mod/ibis view.php?id 3300701 HYS 202 Winter17-TOVAR I Activities and Due Dates I HW6, Ch 10 Temperature Gradeloo 3h/2017 11:00 PM ter Print Calculator Periodic Table Question 12 of 12 Mapoa. Sapling Learning What is the temperature of a sample of gas, when the average translational kinetic energy of a molecule in the sample is 8.27 x102 J? What is the total translational kinetic energy of all the molecules of this sample, when it contains 1.71 moles gas? O Previous ® cave svirw Soutor 0 Check Answer O i Exit

Explanation / Answer

:  E = (3/2)KbT
T = (2/3)E/Kb
Kb = Boltzmann constant = 1.38 × 10^-23 J/K
T = ((2/3) × 8.27 × 10^-21J) / (1.38 × 10^-23 J/K)
T = 399.57K

2.multiply 1.71 x 6.022x10^23 (Avogadros number(
to get 1.03x10^24 (molecules i believe)
then 1.03x10^24 x 8.27 × 10-21 J to get the total KEtr=10751J

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.