Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

13. The figure shows a uniform 2.9 T magnetic field that is normal to the plane

ID: 1538961 • Letter: 1

Question

13. The figure shows a uniform 2.9 T magnetic field that is normal to the plane ofa single conducting loop which has a resistance R 7.50 n The loop initially has an area of0.25 m, and it is compressed so that its area is reduced to a final area of 0.10 m over a period of 1.50 s. The magnetic field is pointing in to the page and does not change with time.) a. What is the magnitude of the average induced emfin the loop? (10 pts.) b. What is the average induced current around the loop? (5 pts.) What is the direction of the induced current around the loop? (Specify clockwise or and explain your reasoning, pts The an ction or t induced cum nt is Cloo his is e fie a nel because the he Crr then 14. For each of the three sheets of polarizing material shown in the drawing, the orientation of the Clokua transmission axis is labeled relative to the vertical. The incident unpolarized and lou intensity wim the of beam transmitted through the three sheets when 0, 19.0, 0, 55.00, 0, 100.0°? the first sheet on the left? (5 pts.) a. What is the intensity of the beam after passing through b. What is the intensity of the beam after through the middle sheet? (5 pts.) (5 pts) c. What is the intensity of the beam after passing through the last sheet on the right? Transmitted beam

Explanation / Answer


13

induced emf = -dphi /dt

phi = B*A cos theta

dphi/dt = -BdA/dt


emf = -BdA/dt
= -(2.9)((0.25-0.10)/(1.5))= - 0.29 V


inducec current i = e.R = -0.29/7.5 A = 0.03867 A

the induced curren is in the clockwise direction

14


Malus law says that


I = I0 cis^2 theta

given
theta1 = 19 degrees

theta2 = 55 degrees

theta3 = 100 degrees and I0 = 1260w/m2

I1 = I0 cos^theta1 = 1260 sos^2(19) = 1126.45 W/m2

I2 = I1 cos^2 theta2 = 1126.45*cos^2(55) = 370.59 W/m2

I3 = I2cos^2 theta3 = 370.590 cos^2(100) = 11.175 W/m2

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote