A baseball player (during a pitching motion) exerts an average horizontal force

Question

A baseball player (during a pitching motion) exerts an average horizontal force of 118N against the 0.15kg baseball while moving it through a horizontal displacement of 4m before releasing it. If the baseball’s velocity at the start of pitching was zero, how fast was the ball moving at the instant of release? A baseball player (during a pitching motion) exerts an average horizontal force of 118N against the 0.15kg baseball while moving it through a horizontal displacement of 4m before releasing it. If the baseball’s velocity at the start of pitching was zero, how fast was the ball moving at the instant of release?

Explanation / Answer

force = mass * acceleration

118 = 0.15 * acceleration

acceleration = 786.67 m/s^2

by third equation of motion

v^2 = u^2 + 2as

v^2 = 0 + 2 * 786.67 * 4

v = 79.33 m/s

velocity of ball = 79.33 m/s

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