A 1.5 kg block is connected by a rope across a 50 cm -diameter, 2.0 kg , frictio

Question

A 1.5 kg block is connected by a rope across a 50 cm -diameter, 2.0 kg , frictionless pulley, as shown in the figure. A constant 10 N tension is applied to the other end of the rope. (Figure 1)

Part A

Starting from rest, how long does it take the block to move 30 cm ?

Express your answer using two significant figures.

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Figure 1 of 1

A 1.5 kg block is connected by a rope across a 50 cm -diameter, 2.0 kg , frictionless pulley, as shown in the figure. A constant 10 N tension is applied to the other end of the rope. (Figure 1)

Part A

Starting from rest, how long does it take the block to move 30 cm ?

Express your answer using two significant figures.

SubmitMy AnswersGive Up

Provide FeedbackContinue

Figure 1 of 1

Explanation / Answer

Since rope is massless and pulley is frictionless the tension in rope will be equal to the force applied on it i.e.

T = 10 N

Now the block has gravity acting downwards and tension T acting upwards which gives it an accleration of a.

By newton's second law , Fnet = ma

T - mg = ma

10 - 1.5*9.81 = 1.5a

a = -4.7 m/s2

Hence block will be moving downwards with a = 4.7 m/s2

Also initial velocity u = 0, distance travelled s = 0.3 m, time t = ?

using S = ut + 1/2at2

0.3 = 0 + 0.5*4.7*t2

t2 = 0.128

t = 0.36 s

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