For the system of capacitors shown in the figure below, find the following. (Let

Question

For the system of capacitors shown in the figure below, find the following. (Let C_1 = 6.00 mu F and C_2 = 7.00 mu F.) the equivalent capacitance of the system 4.75 Your response is within 10% of the correct value. This may be due to roundoff error or you could have a mistake in your calculation. Carry out all intermediate four-digit accuracy to minimize roundoff error the charge on each capacitor on C_1 320 Your response differs from the correct answer by more than 10% double check your calculation mu C on C_2 139.5 mu C on the 6.00 mu F capacitor 48.8 Your response differs from the correct answer by more than 10% double check your calculation mu C on the 2.00 mu F capacitor 69.75 Your response differs from the correct answer by more than 10% double check your calculation mu C the potential sufferance across each capacitor across C_1 32.5 Your response differs from the correct answer by more than 10% double check your calculation mu C

Explanation / Answer

In here,

a.)

for series combination
1/c3= 1/c1 + 1/6 = 1/6 + 1/6 = 1/3F
c' = 3 F

1/c4= 1/c2 + 1/2 = 1/7 + 1/2 = 9/14F
c'' = 1.55F

now c' and c'' are in parallel so
c = c' + c''

c = 4.55 F

Total capacitance in circuit is 4.55 F

b)
The Q is identical for capacitors which are in series.
Q = C * V

Q1 = 3 * 90 = 270 C

also

Q2 = 1.55 *90 = 139.5C

C).
Potential difference accross each capcacitor

v1 = Q/c1 = 270 / 6= 45 V
V2(6F) = 90-45= 45 V

also

V3(2F) = Q2/2.00 = 139.5/2 = 69.75 V
V4 = 90 - 69.75 = 20.25 V

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