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1. A.) A 20.4 mH inductor, an 8.00 resistor, and a 6.00 V battery are connected

ID: 1539396 • Letter: 1

Question

1.

A.) A 20.4 mH inductor, an 8.00 resistor, and a 6.00 V battery are connected in series. The switch is closed at t=0. Find the voltage drop across the resistor after one time constant has passed.

B.) A 20.4 mH inductor, an 8.00 resistor, and a 6.00 V battery are connected in series. The switch is closed at t=0. Find the voltage drop across the inductor at t=0.

C.) How much energy is stored in a 42.1 mH inductor at an instant when the current is 2.00 A?

D.) What is the resistance of a light bulb that uses an average power of 82.0 W when connected to a 60 Hz power source with a peak voltage of 170 V?

E.) An AC voltage source has an output voltage given by V(t)=V0sin(377t) where V0=154 V. Find the rms voltage output.

F.) An AC voltage source has an output voltage given by V(t)=V0sin(377t) where V0=154 V. Find the frequency of the source.

Explanation / Answer


A)


voltage drop across inductor

VL = V*( 1-e^-(Rt/L) )


VR = V - VL

VR = e^-(t/T)

for t = T

VR = V*e^-1

VR = 2.21 V

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B)

voltage drop across inductor

VL = V*( 1-e^-(Rt/L) )

VL = 6*(1-e^-1)

VL = 3.79 V


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C)

energy stored E = (1/2)*L*I^2

E = (1/2)*20.4*10^-3*2^2


E = 40.8 mJ

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D)

power P = Vrms^2/R

Vrms = Vmax/sqrt2

P = Vmax^2/(2R)

82 = 170^2/(2*R)

Resistance R = 172.22 ohm

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E)

Vrms = Vmax/sqrt2 = 154/sqrt2 = 109 V

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F)

frequency f = w/(2pi) = 377/(2pi) = 60 Hz <<<<<<<-------answer