1. A.) A 20.4 mH inductor, an 8.00 resistor, and a 6.00 V battery are connected
ID: 1539396 • Letter: 1
Question
1.
A.) A 20.4 mH inductor, an 8.00 resistor, and a 6.00 V battery are connected in series. The switch is closed at t=0. Find the voltage drop across the resistor after one time constant has passed.
B.) A 20.4 mH inductor, an 8.00 resistor, and a 6.00 V battery are connected in series. The switch is closed at t=0. Find the voltage drop across the inductor at t=0.
C.) How much energy is stored in a 42.1 mH inductor at an instant when the current is 2.00 A?
D.) What is the resistance of a light bulb that uses an average power of 82.0 W when connected to a 60 Hz power source with a peak voltage of 170 V?
E.) An AC voltage source has an output voltage given by V(t)=V0sin(377t) where V0=154 V. Find the rms voltage output.
F.) An AC voltage source has an output voltage given by V(t)=V0sin(377t) where V0=154 V. Find the frequency of the source.
Explanation / Answer
A)
voltage drop across inductor
VL = V*( 1-e^-(Rt/L) )
VR = V - VL
VR = e^-(t/T)
for t = T
VR = V*e^-1
VR = 2.21 V
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B)
voltage drop across inductor
VL = V*( 1-e^-(Rt/L) )
VL = 6*(1-e^-1)
VL = 3.79 V
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C)
energy stored E = (1/2)*L*I^2
E = (1/2)*20.4*10^-3*2^2
E = 40.8 mJ
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D)
power P = Vrms^2/R
Vrms = Vmax/sqrt2
P = Vmax^2/(2R)
82 = 170^2/(2*R)
Resistance R = 172.22 ohm
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E)
Vrms = Vmax/sqrt2 = 154/sqrt2 = 109 V
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F)
frequency f = w/(2pi) = 377/(2pi) = 60 Hz <<<<<<<-------answer
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