831 moles of a monatomic ideal gas in a cylinder with a piston has a temperature

Question

831 moles of a monatomic ideal gas in a cylinder with a piston has a temperature of 286 K and a pressure of 4.41 × 105Pa. The cylinder is connected to a reservoir with a temperature of 318 K and the gas inside the cylinder is allowed to increase in temperature to 318 K using a quasi-static constant-pressure process.

What is the change in entropy of the gas during this process? (To calculate this, we need to add up the infinitesimal amounts of energy added during each infinitesimal increase in temperature using integration.) ??????

Explanation / Answer

heat supplied at constant pressre process

dQ = n*Cp*dT = n*(5/2)*R*dT

change in entropy S = integral dQ/T   from T1 = 286 to T2 = 318 K

S = n*(5/2)*R*(lnT2 - lnT1)

S = 831*(5/2)*8.314*(ln318-ln286)

S = 1831.89 J/K <<<<<=====answer

Related Questions

Navigate

• Browse (All)
• Browse 8
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.