Consider a 71.0-kg man standing on a spring scale in an elevator. Starting from

Question

Consider a 71.0-kg man standing on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.14 m/s in 0.700 s. It travels with this constant speed for the next 5.00 s. The elevator then undergoes a uniform acceleration in the negative y direction for 1.90 s and comes to rest. (a) What does the spring scale register before the elevator starts to move? N (b) What does the spring scale register during the first 0.700 s? N (c) What does the spring scale register while the elevator is traveling at constant speed? N (d) What does the spring scale register during the time it is slowing down? (a) What does the spring scale register before the elevator starts to move? N (b) What does the spring scale register during the first 0.700 s? N (c) What does the spring scale register while the elevator is traveling at constant speed? N (d) What does the spring scale register during the time it is slowing down? N

Explanation / Answer

What does the spring scale register before the elevator starts to move? = mg =71 x 9.8 = 695.8 N

What does the spring scale register during the first 0.700 s? = 695.8+ 71 ( 1.14/ 0.7) = 811.428 N

What does the spring scale register while the elevator is traveling at constant speed? = 695.8

What does the spring scale register during the time it is slowing down? =695.8 - 71 (1.14/1.90) = 643.11 N apprx

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