all please A 10-kg box sitting on a horizontal surface is pulled by a 5.0 N fric

Question

all please

A 10-kg box sitting on a horizontal surface is pulled by a 5.0 N friction force retards the motion. What is the acceleration of the object? A) 0.20 m/s^2 B) 0.30 m/s^2 C) 0.50 m/s^2 D) 5.0 m/s^2 A horizontal force of 5.0 N accelerates a 4.0 kg mass from rest. at a rate of 0.50 m/s^2 in the positive direction. What friction force acts on the mass? A) 2.0 N B) 300 N C) 4.0 N D) 5.0 N An antitank weapon fires a 3.00 Kg rocket which acquires a speed of 50.0 m/s after travelling 90.0 cm down a launching tube. Assuming the rocket was accelerated uniformly. What is the average force act5ed on it?

Explanation / Answer

1) acceleration = net force/mass

=> 5-3 /10

= 0.2 m/s2 ( option A)

2) let friction force be x

acceleration = net force/mass

0.50 = (5-x)/4

x = 3 N which is option (B)

3)

using equation of motion to find acceleration

v2- u2 = 2*a*S

2500 - 0 = 2 * (a ) * (90/100)

1388.88 m/s2

force = m*a = 1388.88*3

= 4166.6 N

= 4.17 x 10^3 option (A)

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