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True or False 1. Resistors always dissipate power whenever there is current and

ID: 1541804 • Letter: T

Question

True or False

1. Resistors always dissipate power whenever there is current and convert electrical potential energy into heat. This is also called Ohmic losses or Joule heating.

2. A kilowatt-hour is a unit of power, which is equal to one thousand Watt per hour.

3. Moving from the negative to positive terminal of a battery decreases your potential.

4. A kilowatt-hour is a unit of energy, which is equal to the amount of energy converted or consumed in one hour by a device working with a power at the rate of one thousand Watts.

5. Moving from the negative to positive terminal of a battery increases your potential.

6. One kilowatt-hour is equal to 3.6 x 106 Joule.

7. When the potential drop (voltage) across the resistor, DeltaV, is fixed, the rate of Joule heating is reversely proportional to R.

8. Regular metal wires have very little resistance comparing to the actual resistors we use in a circuit. In general, it is ok to consider there is no resistance and voltage drop in short metal wires, even when a current flows.

9. Moving from the negative to positive terminal of a battery increases your potential. If current flows in that direction the battery supplies power.

10. When the current through the resistor, I, is fixed, the rate of Joule heating is reversely proportional to R.

11. When the current through the resistor, I, is fixed, the rate of Joule heating is proportional to R.

12. Moving across a resistor in the direction of current increases your potential.

13. When the potential drop (voltage) across the resistor, Delta-V, is fixed, the rate of Joule heating is proportional to R.

14. The rate of Joule heating (the power dissipated by the resistor) for a resistor is P = I the product of current and Delta-V the voltage across the resistor.

15. Power is change in energy per unit time. When the potential difference crossing a circuit element is Delta-V, the power (energy per unit time) to move current through the circuit element is P=d (DeltaU)/dt =d(q DeltaV)/dt = (dq/dt) DeltaV= I DeltaV, which is the product of the current and the potential difference.

16. Moving across a resistor in the direction of current decreases your potential.

Explanation / Answer

1)True

2)False

3)False

4)True

5)False

6)True

7)True

8)True

9)True

10)False

11)True

12)False

13)Falde

14)True

15)True

16)True

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