(6%) Problem 2: A negative charge of q 7.6 x 10 17 and m 8.9 x 10 20 kg C enters
ID: 1542136 • Letter: #
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(6%) Problem 2: A negative charge of q 7.6 x 10 17 and m 8.9 x 10 20 kg C enters a magnetic ficld B 1.9 T with initial velocity v 430 m/s, as shown in the The magnetic field points into the screen. figure. Randomized Variables X X X X X X 7.6 x 10-17C m 8.9 x 10 k 1.9 430 m/s Otheexpertta.com 13% Part (a) Which direction will the magnetic force be on the charge A 13% Part (b) Express the magnitude of the magnetic force, F, in terms of q, v, and B Grade Summary Deductions 0% Potential 100% 7 8 9 HOME Submissions Attempts remaining: 7 MAN 4 5 6 (49 per attempt detailed view 1 2 3 END BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints 0% deduction per hint. Hints remaining 1 Feedback 0% deduction per feedback. A 13% Part (c) Calculate the magnitude of the force F, in newtons. A 13% Part (d) Under such a magnetic force, which kind of motion will the charge undergo A 13% Part (e) Express the centripetal acceleration of the particle in terms of the force F and the mass m. A 13% Part (f Calculate the magnitude of a in meters per square second A 13% Part g Express the radius, R, of the circular motion in terms of the centripetal acceleration a and the speed v A 13% Part (h) Calculate the numerical value of the radius R, in meters.Explanation / Answer
b) the magnetic force F = q (v X B)
c) value of the magnetic force = 7.6x10^-17 x 430x1.9 = 6.2092x10^-14 N
D) the circular motion of a charged particle in the presence of a uniform magnetic field
e) centripetal accele. = qvB = mv^2/ r
where r = mv/qB
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