The Franck-Hertz experiment involved shooting electrons into a low-density gas o

Question

The Franck-Hertz experiment involved shooting electrons into a low-density gas of mercury atoms and observing discrete amounts of kinetic energy loss by the electrons. Suppose Instead a similar experiment is done with a very cold gas of atomic hydrogen, so that all of the hydrogen atoms are initially in the ground state. If the kinetic energy of an electron is 11.1 eV just before it collides with a hydrogen atom, how much kinetic energy will the electron have just after it collides with and excites the hydrogen atom? K_final = _______ eV

Explanation / Answer

initial kinetic energy of the electron is 11.1 eV

for hydrogen atom

the ground state energy OF HYDROGEN ATOM IS -13.6 Ev

Energy of first exited state is - 3.4 eV

change is - 3.4 - ( - 13.6) eV

= 10.2 eV

the electron energy after collision is 11.1 - 10.2

final kE of electron is 0.9 eV

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