As shown in the figure below, a green bead of mass 20 g slides along a straight

Question

As shown in the figure below, a green bead of mass 20 g slides along a straight wire. The length of the wire from point to point is 0.800 m, and point is 0.400 m higher than point A constant friction force of magnitude 0.0150 N acts on the bead. (a) If the bead is released from rest at point, what is its speed at point ? m/s (b) A red bead of mass 20 g slides along a curved wire, subject to a friction force with the same constant magnitude as that on the green bead. If the green and red beads are released simultaneously from rest at point, which bead reaches point with a higher speed? the green bead the red bead both beads arrive with equal speed

Explanation / Answer

mgh - fd = (1/2)mv^2

(20/1000) (9.8) (.4) - (.01) (.8) == (1/2) (20/1000) (v)^2

Solve for v: v = 3.2 m/s^2(approximately)

The green bead will reach point B at a higher speed because it traveled a shorter distance, and therefore there was a shorter distance for the frictional force to act

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