give the formul The heaviest invertebrate is the giant squid, which is estimated
ID: 1544368 • Letter: G
Question
give the formul The heaviest invertebrate is the giant squid, which is estimated to have a weight of about 0.28 tons spread out over its length of 31 feet. What is its weight in newtons? _____ N A football punter accelerates a football from rest to a speed of 12 m/s during the time in which his toe is in contact with the ball (about 0.15 s). If the football has a mass of 0.44 kg, what average force does the punter exert on the ball? _____ N A bag of sugar weighs 3.00 lb on Earth. What would it weigh in newtons on the Moon, where the free-fall acceleration is one that on Earth? _____ N Repeat for Mercury, where g is 0.367 times that on Earth. _____ N Find the mass of the bag of sugar in kilograms at each of the three locations. Earth _____ kg Moon _____ kg Mercury _____ kg A freight train has a mass of 1.3 times 10^7 kg. If the locomotive can exert a constant pull of 8.0 times 10^5 N, how long does it take to increase the speed of the train from rest to 62 km/h? _____ min A76-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 836 N. What is the acceleration of the elevator? _____ m/s upwardExplanation / Answer
Solution:
1) 1 ton = 1000 kg
so 0.28 tons =0.28 * 1000 =280 kg
weight = 280 x 9.8 = 2744 N
2) The average force exerted by the punter is calculated from Impulse equation.
Ft = m(vf-vi)
F = m(vf-vi) / t = 0.44(12-0) / (0.15)
= 35.2 N
3) 1 pound force = 4.4 N
3 lb force = 3 x 4.4 = 13.2 N
mass = 13.2 / 9.8 = 1.35 kg
weight on moon = mg = (1.35)(1/6*9.8) =2.21 N on Moon
weight on Mercury = (1.35)(0.367 * 9.8) = 4.86 N on mercury
Weight changes from place to place . But mass is change less whatever mass is on earth , it is same everywhere.
mass on earth = 1.35 kg
mass on moon = 1.35 kg
mass on mercury = 1.35 kg
4) m =1.3 x10^7 kg
F =8 x 10^5 N
It starts from rest ; so vi = 0 and final velocity = 62 kmph = 17.2 m/s
Impulse is defined as the product of force and time .
F t = m(vf-vi)
=> t = m(vf-vi)/F = (1.3 x 10^7) (17.2 - 0 ) / ( 8 x10^5 )
= 2.8 x10^2 seconds = 4.7 minutes
5) mass of the person = m = 76kg
As the elevator rises, a person experiences an increase in weight .
m(g+a) = Fn
=> a = Fn /m -g = 836 / 76 -9.8 = 11 -9.8 =1.2 m/s2
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