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M inbox (8,400) nafisa abu10 x lindseyjonesuniversitynet x Hwa3 c O www.webassign.net/webl student Assignment-Responseslsubmit?depa15688532 Submit Answer Save Progress Practice Another Version 4. O -2 points SerCP11 1 P062. A person walks 29.0° north of east for 2.60 km. How far due north and how far due east would she have to walk to arrive at the same location? north east Need Help? LRead 5. -3 points SerCP10 3.P013 A girl delivering newspapers covers her route by traveling 4.75 blocks west, 4.75 blocks north, and then 7.50 blocks east. (a) What is her resultant displacement? magnitude blocks north of east direction (b) What is the total distance she travels? blocks 6. O -1 points sercp11 3.Po08.Explanation / Answer
4)
north = 2.60*sin(29) = 1.26 km
east = 2.6*cos(29) = 2.27 km
5)
let east be +x axis
displacement in x- direction, x = 7.5 - 4.75
= 2.75 blocks
displacement in y-direction, y = 4.75 blocks
resultant dispalcement = sqrt(x^2 + y^2)
= sqrt(2.75^2 + 4.75^2)
= 5.49 blocks
direction : theta = tan^-1(y/x)
= tan^-1(4.75/2.75)
= 59.9 degrees north of east
b) distance travelled = 4.75 + 4.75 + 7.5 = 17 blocks
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