find the equivalent capacitance of the combination. Assume c1=10micro farad C2=5
ID: 1545387 • Letter: F
Question
find the equivalent capacitance of the combination. Assume c1=10micro farad C2=5micro farad C3= 4micro farad I tryed to solve it in two diff ways 1) saying that c3 and c1 (series)/then c13 and c2 (parallel) 2) c1 and c2 (parallel) / then c12 and c3 (series)Both of the ways are same but somthing is in the first step and the other is in the second
The results i get from both of the ways are not same why?!!!
Can you pls tell me the reason no need for solving it.
I need an explanation only for why the both results are not same and if one of the is wrong!
C2=5micro farad C3= 4micro farad I tryed to solve it in two diff ways 1) saying that c3 and c1 (series)/then c13 and c2 (parallel) 2) c1 and c2 (parallel) / then c12 and c3 (series)
Both of the ways are same but somthing is in the first step and the other is in the second
The results i get from both of the ways are not same why?!!!
Can you pls tell me the reason no need for solving it.
I need an explanation only for why the both results are not same and if one of the is wrong!
Fig. 26-28 Exercise 13, Problems 14 and 28
Explanation / Answer
We cannot take C1 and C3 in series because the charges through both the capacitor is different. As the charges distributed at the junction of C1 and C2 hence we have to find the equivalent capacitance of these(C1 &C2) paralleled connected capacitors first I.e C12.
Now this c12 is in series with c3 to get net capacitance of the circuit.
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