D PeopleSoft session expired x VA Homework 9 x C Chegg Study Guided solution x C

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D PeopleSoft session expired x VA Homework 9 x C Chegg Study Guided solution x C www.webassign.net/ /last?dep 15074203 web/Student/Assignment-Responses 12. -1 points CJ10 9.P070 My Notes A solid disk rotates in the horizontal plane at an angular velocity of 0.050 rad/s with respect to an axis perpendicular to the disk at its center. The moment From above, sand is dropped straight down onto this rotating disk, so that a thin the disk is 0.13 kg m uniform ring of sand is formed at a of inertia of distance of 0.40 m from the axis. The sand in the ring has a mass of 0.50 kg. After all the sand is in place, what is the angular velocity of the disk? rad/s Additional Materials La Section 9.1 13. -1 points CJ10 9.P07 My Notes A solid cylindrical disk has a radius of 0.16 m. It is mounted to an axle that is perpendicular to the circular end of the disk at its center. When a 45 N force is applied tangentially to the disk, perpendicular to the radius, the disk acquires an angular acceleration of 110 rad/s2. What is the mass of the disk? kg Additional Materials Section 9.1

Explanation / Answer

As you asked multiple question so, l am bound to answer first one.

12.

Given that,

initial angular velocity w1 = 0.05 rad/s

initial moment of inertia l1 = 0.13 kg*m^2

moment of inertia of ring = m*r^2 = 0.5*(0.4)^2 = 0.08 kg*m^2

total moment of inertia l2 = 0.13 + 0.08 = 0.21 kg*m^2

let, final velocity = w2

According to conservation of angular momentum,

l1*w1 = l2*w2

w2 = 0.13*0.05 / 0.21

w2 = 0.030 rad/s

w2 =

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