ibiscms/mod/ibis/view.php?id 3194347 Gradebook 319/2017 11:55 PM A 25/14 3/15/20

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ibiscms/mod/ibis/view.php?id 3194347 Gradebook 319/2017 11:55 PM A 25/14 3/15/2017 08:35 PM Print Calculator Periodic Table Question 8 of 14 Inoontact S incorrect Sapling Learning A very long solenoid of inner radius 2.25 cm creates an oscillating magnetic field of the form. EOS CU MAT Here Brax 0.00425 T and 369 radis. What is the maxiumum value of the induced electric field at a point 1.45 cm perpendicular from the axis of the Number 0.0176 What is the maximum value of the induced electric field at a point 5.05 cm perpendicular from the axis of the solenoid? Number 0.0889 Vi m There is a hint available! an the divider bar again lo hide lhe hint Previous Gve up sa Chack Answer Next

Explanation / Answer

Magnitude of Induced electric field with in the solenoid
E = dB/dt ( r/2)
where is the perpnedicular distance of point from axis.
B = 0.00425 cos(369t)
dB/dt = - 0.00425 x 369 sin(369t)
Maximum value of dB/dt = 0.00425 x 369 = 1.56825
Hence maximum inducde electric field at distance of 1.45 cm (that is inside solenoid)
Em = 1.56825 x0.0145 /2 = 0.01137 V/m

For point outside solenoid, induced electric field is given by
E = dB/dt ( R2 / 2r) where R is radius of solenoid)
Hence maximum electric field at 5.05 cm
Em = 1.56825 x 0.02252 / 2 x 0.0505
   = 0.00786 V/m

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