handwritten with explanation please 8. A shopper at the Fries’ market place push
ID: 1547334 • Letter: H
Question
handwritten with explanation please 8. A shopper at the Fries’ market place pushes a 13.0-kg shopping cart at a constant velocity for a distance of 58.7 m on a level surface. He pushes in a direction 24.50 below the horizontal. A 53.8 N frictional force opposes the motion of the cart. (a) What is the magnitude of the force that the shopper exerts on the cart? (b) What is the work done by the pushing force? (c) What is the work done by the frictional force? (d) What is the work done by the gravitational force?
Explanation / Answer
(a) Fcos24.5-Ff= ma
F cos24.5-53.8= m(0)
F= 53.8/cos24.5
F=59.12 N
(b) W= F d cos24.5
W= 59.12 (58.7) cos 24.5
W=3158.1 J
(c) W= Ff d
W= -53.8(58.7)
W=-3158.1 J
(d) Work by gravity= F d cos90=0
so work done by gravity=0
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