An object is placed 20.6 cm to the left of a converging lens of focal length 25.

Question

An object is placed 20.6 cm to the left of a converging lens of focal length 25.0 cm. A diverging lens of focal length 10.0 cm is 25.0 cm to the right of the converging lens. (a) Find the distance of the final image from the second lens. Right is positive, left is negative.

(b) Find the magnification of the final image.

An object is placed 20.6 cm to the left of a converging lens of focal length 25.0 cm. A diverging lens of focal length 10.0 cm is 25.0 cm to the right of the converging lens. (a) Find the distance of the final image from the second lens. Right is positive, left is negative.

(b) Find the magnification of the final image.

Explanation / Answer

Apply lens equation for converging lens

1/f1 = 1/p1 + 1/q1

1/q1 = 1/25 - 1/20.6

q1 = -117.04 cm

p2 = 117.04 + 25 = 142.04 cm

Apply lens equation for diverging lens

1/f2 = 1/q2 + 1/p2

1/q2 = 1/f2- 1/p2

= 1/-10 - 1/142.04

q2 = -9.34 cm ( negative)

the distance of the final image from the second lens is d= 25 + 9.34 = 34.34 cm

M = ( -q1/p1) ( -q2/p2)

=- ( -117.04/20.6) ( - (-9.34/142.04 cm)

=0.373

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