A uniform electric field has magnitude E and is directed in the negative x direc

Question

A uniform electric field has magnitude E and is directed in the negative x direction. The potential difference between point a (at x= 0.65 m ) and point b (at x= 0.90 m ) is 280 V . Part A Which point, a or b, is at the higher potential? a b S Part B Calculate the value of E. Express your answer using two significant figures. E = N/C S Part C A negative point charge q=0.200C is moved from b to a. Calculate the work done on the point charge by the electric field. Express your answer using two significant figures. W =

Explanation / Answer

Part A

Electric field is towards our left. Electric field is always flow from higher to lower potential So, for the first query, B will be at higher potential than A.
Part B

Second, E = V/d = 280/(0.90-0.65) = 1120 V/m

Part C

Third, p d 280 V means that work done in taking 1 Coulomb charge is 280 joule
So in taking 0.20 x 10^-6 C the work, of course, done by electric field = 280*0.2 micro joule
ie W = 56 micro joule.

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